Power Rule of Derivatives (Calculus)

Power Rule of Derivatives

The power rule of differentiation says that if the given function is of the form xnx^n, where nn is any constant, then we can differentiate the function in the following way:

Basics of Differentiation

This section covers key differentiation concepts, rules, and applications.

Rules & Techniques of Differentiation

This section introduces the fundamental rules and methods used to differentiate functions efficiently.

Note: The Power Rule is often used alongside the Chain Rule when dealing with composite functions. For a deeper dive into the conditions required for a derivative to exist, see our guide on Differentiability.

f(x)=xnf(x) = x^n f(x)=ddx(xn)f'(x) = \frac{d}{dx}(x^n) f(x)=nxn1f'(x) = nx^{n-1}

This means that in such a case the differentiation is equal to the variable raised to 1 less than the original power and multiplied by the original power. Or, simply the power will be dropped in front of the variable (i.e. xx in this case) and the power is reduced by one.

Example: Differentiate the function f(x)=x3f(x) = x^3 with respect to xx.

Given:

f(x)=x3f(x) = x^3 f(x)=ddx(x3)\Rightarrow f'(x) = \frac{d}{dx}(x^3) f(x)=3x31\Rightarrow f'(x) = 3x^{3-1} f(x)=3x2\Rightarrow f'(x) = 3x^2

Derivative Slope Diagram

Standard Derivative Rules Table

Function f(x)f(x)Derivative f(x)f'(x)
cc (constant)00
xnx^nnxn1nx^{n-1}
sin(x)\sin(x)cos(x)\cos(x)
cos(x)\cos(x)sin(x)-\sin(x)
exe^xexe^x
ln(x)\ln(x)1x\frac{1}{x}

Example 2: Complex Polynomial

Find the derivative of g(x)=4x32x2+5x7g(x) = 4x^3 - 2x^2 + 5x - 7.

Solution:

g(x)=ddx(4x3)ddx(2x2)+ddx(5x)ddx(7)g'(x) = \frac{d}{dx}(4x^3) - \frac{d}{dx}(2x^2) + \frac{d}{dx}(5x) - \frac{d}{dx}(7) g(x)=4(3x2)2(2x)+5(1)0g'(x) = 4(3x^2) - 2(2x) + 5(1) - 0 g(x)=12x24x+5g'(x) = 12x^2 - 4x + 5
# Check with Python SymPy import sympy as sp x = sp.Symbol('x') g = 4*x**3 - 2*x**2 + 5*x - 7 print(sp.diff(g, x))

Output:

12*x**2 - 4*x + 5
#Calculus#Math#Advanced Level
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